Lakewood Hills, Indiana
Lakewood Hills, Indiana | |
---|---|
Lakewood Hills | |
Coordinates: 38°00′09″N 87°30′51″W / 38.00250°N 87.51417°WCoordinates: 38°00′09″N 87°30′51″W / 38.00250°N 87.51417°W | |
Country | United States |
State | Indiana |
County | Vanderburgh |
Township | Center |
Elevation | 390 ft (119 m) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 47711 |
Area code(s) | 812, 930 |
GNIS feature ID | 437567 |
Lakewood Hills is an unincorporated community in Center Township, Vanderburgh County, in the U.S. state of Indiana.[2]
It is located within the city limits of Evansville.
Geography[]
Lakewood Hills is located at 38°00′09″N 87°30′51″W / 38.00250°N 87.51417°W.
References[]
- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved 2016-07-20.
- ^ "Lakewood Hills, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2016-07-20.
Categories:
- Unincorporated communities in Vanderburgh County, Indiana
- Unincorporated communities in Indiana
- Southwestern Indiana geography stubs