Sękowice, Lubusz Voivodeship

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Sękowice
Village
Sękowice is located in Poland
Sękowice
Sękowice
Coordinates: 51°55′N 14°43′E / 51.917°N 14.717°E / 51.917; 14.717
CountryPoland Poland
VoivodeshipLubusz
CountyKrosno Odrzańskie
GminaGmina Gubin

Sękowice [sɛnkɔˈvit͡sɛ] (German: Schenkendorf) is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately 4 kilometres (2 mi) south of Gubin, 30 km (19 mi) south-west of Krosno Odrzańskie, and 55 km (34 mi) west of Zielona Góra.

Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II).

References[]

  1. ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.


Coordinates: 51°55′00″N 14°43′00″E / 51.9167°N 14.7167°E / 51.9167; 14.7167


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