Sand Creek Township, Jennings County, Indiana

From Wikipedia, the free encyclopedia
Sand Creek Township
Township
Location in Jennings County
Location in Jennings County
Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694
CountryUnited States
StateIndiana
CountyJennings
Government
 • TypeIndiana township
Area
 • Total27.95 sq mi (72.4 km2)
 • Land27.72 sq mi (71.8 km2)
 • Water0.23 sq mi (0.6 km2)  0.82%
Elevation
725 ft (221 m)
Population
 (2010)
 • Total872
 • Density31.5/sq mi (12.2/km2)
GNIS feature ID0453833

Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2010 census, its population was 872 and it contained 365 housing units.[1]

Geography[]

According to the 2010 census, the township has a total area of 27.95 square miles (72.4 km2), of which 27.72 square miles (71.8 km2) (or 99.18%) is land and 0.23 square miles (0.60 km2) (or 0.82%) is water.[1] The streams of Bear Creek, Fish Creek, Ice Creek, Millstone Creek, Poplar Root Creek and Rock Creek run through this township.

Unincorporated towns[]

Adjacent townships[]

Cemeteries[]

The township contains three cemeteries: Bear Creek, Day and Fish Creek.

Major highways[]

References[]

  1. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.

External links[]

Retrieved from ""