Sand Pond (New York)
| Sand Pond | |
|---|---|
  Sand Pond Location of Sand Pond within New York | |
| Location | Delaware County, New York |
| Coordinates | 41°54′57″N 75°11′04″W / 41.9157905°N 75.1844678°WCoordinates: 41°54′57″N 75°11′04″W / 41.9157905°N 75.1844678°W |
| Type | Lake |
| Surface area | 48 acres (0.075 sq mi) |
| Surface elevation | 1,480 feet (450 m)[1] |
| Settlements | |
Sand Pond is a small lake located south of the hamlet of in Delaware County, New York. The pond is also directly adjacent to . Sand Pond drains south via an unnamed creek that flows into Bouchoux Brook. Pierce Pond is located north of Sand Pond.
See also[]
- List of lakes in New York
References[]
- ^ "Sand Pond". Geographic Names Information System. United States Geological Survey. Retrieved 2018-09-25.
Categories:
- Lakes of New York (state)
- Lakes of Delaware County, New York