Seward Lake
Seward Lake | |
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![]() ![]() Seward Lake Location of Seward Lake within New York State | |
Location | Otsego County, New York |
Coordinates | 42°32′23″N 74°50′27″W / 42.53972°N 74.84083°WCoordinates: 42°32′23″N 74°50′27″W / 42.53972°N 74.84083°W |
Primary outflows | Schenevus Creek |
Surface area | 28 acres (0.044 sq mi) |
Surface elevation | 1,237 feet (377 m)[1] |
Settlements | Schenevus |
Seward Lake is a small lake in Otsego County, New York. It is located west of Schenevus. Seward Lake drains west via an unnamed stream into Schenevus Creek.
References[]
- ^ "Hudson Lake". Geographic Names Information System. United States Geological Survey. Retrieved 2018-03-12.
Categories:
- Lakes of New York (state)
- Lakes of Otsego County, New York