The 1832 United States presidential election in Maryland took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
While Maryland voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson, by a mere four votes, this is irrelevant because electors weren't awarded based on the statewide vote. They were chosen in four district elections. A total of ten electoral votes were allocated, with five going to Clay and three to Jackson, while two electors failed to cast votes. In terms of raw votes cast, Clay's four-vote margin is the smallest between two major candidates in any state in any presidential election in United States history.
Results[]
1832 United States presidential election in Maryland District 1 - Western (4 Electors) [1]
Party
Candidate
Votes
Percentage
Electoral votes
National Republican
Henry Clay
8,458
62.398%
4
Democratic
Andrew Jackson
5,097
37.602%
0
Totals
13,555
100.0%
4
1832 United States presidential election in Maryland District 2 - Baltimore City (2 Electors)
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
Andrew Jackson
5,025
54.190%
2
National Republican
Henry Clay
4,248
45.810%
0
Totals
9,273
100.0%
2
1832 United States presidential election in Maryland District 3 - Baltimore County (1 Elector)
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
Andrew Jackson and Martin Van Buren
2,198
75.663%
1
Democratic
Andrew Jackson and Philip P. Barbour
707
24.337%
0
National Republican
Henry Clay
0
0%
0
Totals
2,905
100.0%
1
1832 United States presidential election in Maryland District 4 - Eastern (3 Electors)
Party
Candidate
Votes
Percentage
Electoral votes
National Republican
Henry Clay
6,454
51.291%
3
Democratic
Andrew Jackson
6,129
48.709%
0
Totals
12,583
100.0%
3
1832 United States presidential election in Maryland statewide (0 Electors) [2]