Election in Illinois
Main article: 1884 United States presidential election
1884 United States presidential election in Illinois
Nominee
James G. Blaine
Grover Cleveland
Party
Republican
Democratic
Home state
Maine
New York
Running mate
John A. Logan
Thomas A. Hendricks
Electoral vote
22
0
Popular vote
337,469
312,351
Percentage
50.17%
46.43%
County Results
[citation needed ]
Blaine
40-50%
50-60%
60-70%
70-80%
Cleveland
40-50%
50-60%
60-70%
Tie
<50%
President before election
Chester A. Arthur
Republican
Elected President
Grover Cleveland
Democratic
The 1884 United States presidential election in Illinois took place on November 4, 1884, as part of the 1884 United States presidential election . Voters chose 22 representatives, or electors to the Electoral College , who voted for president and vice president .
Illinois voted for the Republican nominee, James G. Blaine , over the Democratic nominee, Grover Cleveland . Blaine won the state by a narrow margin of 3.74%.
Results [ ]
1884 United States presidential election in Illinois[1]
Party
Candidate
Running mate
Popular vote
Electoral vote
Count
%
Count
%
Republican
James Gillespie Blaine of Maine
John Alexander Logan of Illinois
337,469
50.17%
22
100.00%
Democratic
Grover Cleveland of New York
Thomas Andrews Hendricks of Indiana
312,351
46.43%
0
0.00%
Prohibition
John Pierce St. John of Kansas
William Daniel of Maryland
12,074
1.79%
0
0.00%
Greenback
Benjamin Franklin Butler of Massachusetts
Absolom Madden West of Mississippi
10,776
1.60%
0
0.00%
Total
672,670
100.00%
22
100.00%
See also [ ]
United States presidential elections in Illinois
References [ ]
show State and district results of the 1884 United States presidential election
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