1888 Belgian general election

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1888 Belgian general election

← 1886 12 June 1888 (1888-06-12) 1890 →

69 of the 138 seats in the Chamber of Representatives
70 seats needed for a majority
  First party Second party
  Auguste Beernaert(03).jpg No image.png
Leader Auguste Beernaert
Party Catholic Liberal
Leader since Candidate for PM
Seats before 98 seats 40 seats
Seats won 66 3
Seats after 98 40
Seat change Steady Steady
Popular vote 31,273 19,967
Percentage 58.44% 37.31%

Belgian Chamber 1886.svg

Belgium Senate 1888.svg

Government before election

Beernaert
Catholic

Government after election

Beernaert
Catholic

Partial general elections were held in Belgium on 12 June 1888.[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.[2]

Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.

Results[]

Chamber of Representatives[]

Party Votes % Seats
Won Total +/–
Catholic Party 31,273 58.4 66 98 0
Liberal Party 19,967 37.3 3 40 0
Others 2,277 4.3 0 0 New
Invalid/blank votes
Total 53,517 100 69 138 0
Registered voters/turnout 73,276
Source: Mackie & Rose,[3] Sternberger et al

Senate[]

Party Votes % Seats
Catholic Party 47
Liberal Party 18
Independents 4
Total 69
Source: Sternberger et al.

References[]

  1. ^ Codebook Constituency-level Elections Archive, 2003
  2. ^ a b Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
  3. ^ Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51
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