1888 United States presidential election in Illinois

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1888 United States presidential election in Illinois

← 1884 November 6, 1888 1892 →
  Benjamin Harrison 1896.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 22 0
Popular vote 370,475 348,351
Percentage 49.54% 46.58%

Illinois Presidential Election Results 1888.svg
County Results

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Illinois took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 22 representatives, or electors to the Electoral College, who voted for president and vice president.

Illinois voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a narrow margin of 2.96%.

Results[]

1888 United States presidential election in Illinois[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 370,475 49.54% 22 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 348,351 46.58% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 21,703 2.90% 0 0.00%
Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 7,134 0.95% 0 0.00%
150 0.02% 0 0.00%
Total 747,813 100.00% 22 100.00%

See also[]

  • United States presidential elections in Illinois

References[]

  1. ^ "1888 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved 23 December 2013.


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