1888 United States presidential election in Indiana

From Wikipedia, the free encyclopedia
1888 United States presidential election in Indiana

← 1884 November 6, 1888 1892 →
  Benjamin Harrison 1896.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 15 0
Popular vote 263,361 261,013
Percentage 49.05% 48.61%

Indiana Presidential Election Results 1888.svg
County Results

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Indiana took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a narrow margin of 0.44%.

Results[]

1888 United States presidential election in Indiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 263,361 49.05% 4 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 261,013 48.61% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 9,881 1.84% 0 0.00%
Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 2,694 0.50% 0 0.00%
Total 536,949 100.00% 15 100.00%

See also[]

Notes[]

References[]

  1. ^ "1888 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.


Retrieved from ""