1888 United States presidential election in Maryland

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1888 United States presidential election in Maryland
Flag of Maryland (pre-1904).png
← 1884 November 6, 1888 1892 →
  StephenGroverCleveland.png Benjamin Harrison 1896.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Allen G. Thurman Levi P. Morton
Electoral vote 8 0
Popular vote 106,188 99,986
Percentage 50.34% 47.40%

Maryland Presidential Election Results 1888.svg
County Results

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Maryland took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a narrow margin of 2.94%.

Results[]

1888 United States presidential election in Maryland[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 106,188 50.34% 8 100.00%
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 99,986 47.40% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 4,767 2.26% 0 0.00%
Total 210,941 100.00% 8 100.00%

See also[]

Notes[]

References[]

  1. ^ "1888 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 23 December 2013.


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