1968 CONCACAF Champions' Cup

1968 CONCACAF Champions' Cup

Tournament details
Dates	26 May – 1 December 1968
Teams	10
Final positions
Champions	Toluca (1st title)
← 1967 1969 →

The 1968 CONCACAF Champions' Cup was the 4th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.

The tournament was played by 10 teams of 10 nations: Netherlands Antilles, Bermuda, El Salvador, United States, Guatemala, Mexico, Honduras, Suriname, Nicaragua, Costa Rica.

It was played from 26 May till 1 December 1968 under the home/away match system. The tournament was split in 3 zones (North American, Central American and Caribbean), each one qualifying the winner to the final tournament, where the winners of the Central and Caribbean zones played a semi-final to decide who was going to play against the Northern champion in the final. The final was scratched and Toluca were declared champions after both semi-finalists, Aurora and Transvaal, were ejected from the competition due to crowd violence.

Club Deportivo Toluca (actually known as Deportivo Toluca FC) from Mexico won the final, and became for the first time in its history CONCACAF champion.^[1][2]

Caribbean zone[]

Scherpenheuvel v Transvaal

22 April 1968 1st leg

Scherpenheuvel

1–1

Transvaal

Transvaal v Scherpenheuvel

2 May 1968 2nd leg

Transvaal

3–1

Scherpenheuvel

• Transvaal won 4–2 on aggregate score.

Northern zone[]

First round[]

Somerset Trojans v NY Greek Americans

26 May 1968 1st leg

Somerset Trojans

2–1

NY Greek Americans

NY Greek Americans v Somerset Trojans

2 June 1968 2nd leg

NY Greek Americans

1–0

Somerset Trojans

NY Greek Americans v Somerset Trojans

Play-off

NY Greek Americans

2–1

Somerset Trojans

New York, New York

• NY Greek Americans won 4–3 on aggregate score.

Second round[]

Toluca v NY Greek Americans

29 September 1968 1st leg	Toluca	4–1	NY Greek Americans	Mexico
CST	Epaminondas 14' 85' (pen.) Ruvalcaba 25' 59'		33' (pen.) Tonorezos

NY Greek Americans v Toluca

6 October 1968 2nd leg	NY Greek Americans	2–3	Toluca	United States
EST			Ruvalcaba Epaminondas

• Toluca won 7–3 on aggregate score.

Central American Zone[]

First round[]

Alajuelense v Aurora

3 April 1968 1st leg	Alajuelense	0–2	Aurora	Costa Rica
CST

Aurora v Alajuelense

7 April 1968 2nd leg	Aurora	0–1	Alajuelense	Guatemala
CST

• Aurora won 2–1 on aggregate score.

Alianza v Olimpia

21 April 1968 1st leg	Alianza	1–2	Olimpia	El Salvador
CST	Odir Jacques		Ricardo Taylor Donaldo Rosales

Olimpia v Alianza

28 April 1968 2nd leg	Olimpia	1–0	Alianza	Honduras
CST	Conrado Flores		Nil

• Olimpia won 3–1 on aggregate score.

Second round[]

Olimpia v Aurora

3 November 1968 1st leg	Olimpia	1–1	Aurora	Honduras
CST

Aurora v Olimpia

10 November 1968 2nd leg	Aurora	4–0	Olimpia	Guatemala
CST

• Aurora won 5–1 on aggregate score.

Semifinals[]

Transvaal v Aurora

27 November 1968 1st leg	Transvaal	1–1	Aurora	Paramaribo, Dutch Guiana
AST

Aurora v Transvaal

1 December 1968 2nd leg	Aurora	0–2	Transvaal	Paramaribo, Dutch Guiana
AST

• At the end of the 2nd leg, Transvaal fans invaded the pitch, but after Aurora fans did the same, a mass brawl broke out between the two sets of fans; both teams were ejected from the competition.

Final[]

As no final was held after Aurora and Transvaal were disqualified from the competition, Mexican side Toluca were declared champions.^[1]

Champion[]

CONCACAF Champions' Cup 1968 Champion
Toluca First title

References[]