1989 Big Eight Conference Men's Basketball Tournament

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1989 Big Eight Conference Men's Basketball Tournament
ClassificationDivision I
Season1988–89
Teams8
Finals siteKemper Arena
Kansas City, MO
ChampionsMissouri (4th title)
Winning coachNorm Stewart (4th title)
MVPDoug Smith (Missouri)
TelevisionRaycom Sports (Quarterfinals, Semi-Finals and Championship)
ABC (Championship game)
← 1988
1990 →
1988–89 Big Eight Conference men's basketball standings
Conf Overall
Team W   L   PCT W   L   PCT
No. 4 Oklahoma 12 – 2   .857 30 – 6   .833
No. 6 Missouri † 10 – 4   .714 29 – 8   .784
Kansas State 8 – 6   .571 19 – 11   .633
Oklahoma State 7 – 7   .500 17 – 13   .567
Iowa State 7 – 7   .500 17 – 12   .586
Kansas 6 – 8   .429 19 – 12   .613
Nebraska 4 – 10   .286 17 – 16   .515
Colorado 2 – 12   .143 7 – 21   .250
† 1989 Big Eight Tournament winner
As of March 3, 2012; Rankings from AP Poll


The 1989 Big Eight Men's Basketball Tournament was held March 10–12 at Kemper Arena in Kansas City, Missouri.[1]

Second-seeded Missouri defeated #1 seed Oklahoma in the championship game, 98–86, to earn the conference's automatic bid to the 1989 NCAA Tournament.

Bracket[]

Quarterfinals
Friday, March 10 		Semifinals
Saturday, March 11 		Championship
Sunday, March 12
         
1 #2 Oklahoma 95
8 Colorado 87
1 #2 Oklahoma 76
5 Iowa State 74
4 Oklahoma State 69
5 Iowa State 88
1 #2 Oklahoma 86
2 #10 Missouri 98
3 Kansas State 73
6 Kansas 65
3 Kansas State 83
2 #10 Missouri 88
7 Nebraska 70
2 #10 Missouri 98

References[]

  1. ^ "1988-89 Big 8 Conference Season Summary". sports-reference.com. Sports Reference. Retrieved March 31, 2019.
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