1990 Big Eight Conference Men's Basketball Tournament

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1990 Big Eight Conference Men's Basketball Tournament
ClassificationDivision I
Season1989–90
Teams8
Finals siteKemper Arena
Kansas City, MO
ChampionsOklahoma (4th title)
Winning coachBilly Tubbs (3rd title)
MVPShaun Vandiver (Colorado)
TelevisionRaycom Sports (Quarterfinals, Semi-Finals and Championship)
ABC(Championship game)
← 1989
1991 →
1989–90 Big Eight Conference men's basketball standings
Conf Overall
Team W   L   PCT W   L   PCT
No. 11 Missouri 12 – 2   .857 26 – 6   .813
No. 1 Oklahoma † 11 – 3   .786 27 – 5   .844
No. 5 Kansas 11 – 3   .786 30 – 5   .857
Kansas State 7 – 7   .500 17 – 15   .531
Oklahoma State 6 – 8   .429 17 – 14   .548
Iowa State 4 – 10   .286 10 – 18   .357
Nebraska 3 – 11   .214 10 – 18   .357
Colorado 2 – 12   .143 12 – 18   .400
† 1990 Big Eight Tournament winner
As of March 3, 2012; Rankings from AP Poll


The 1990 Big Eight Men's Basketball Tournament was held March 9–11 at Kemper Arena in Kansas City, Missouri.[1]

Second-seeded Oklahoma defeated #8 seed Colorado in the championship game, 92–80, to earn the conference's automatic bid to the 1990 NCAA Tournament.

Bracket[]

Quarterfinals
Friday, March 9 		Semifinals
Saturday, March 10 		Championship
Sunday, March 11
         
1 #6 Missouri 88
8 Colorado 92
8 Colorado 82
5 Oklahoma State 72
4 Kansas State 78
5 Oklahoma State 82
8 Colorado 80
2 #1 Oklahoma 92
3 #2 Kansas 118
6 Iowa State 75
3 #2 Kansas 77
2 #1 Oklahoma 95
7 Nebraska 65
2 #1 Oklahoma 78

References[]

  1. ^ "1989-90 Big 8 Conference Season Summary". sports-reference.com. Sports Reference. Retrieved March 31, 2019.
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