2020 Australian Open – Wheelchair women's singles

From Wikipedia, the free encyclopedia
  (Redirected from )
Wheelchair women's singles
2020 Australian Open
ChampionJapan Yui Kamiji
Runner-upNetherlands Aniek van Koot
Final score6–2, 6–2
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends men women
← 2019 · Australian Open · 2021 →

Diede de Groot was the defending champion in this event, but lost to Zhu Zhenzhen in the quarterfinals.

Yui Kamiji won the title, defeating Aniek van Koot in the final, 6–2, 6–2.

Seeds[]

  1. Netherlands Diede de Groot (quarterfinals)
  2. Japan Yui Kamiji (champion)

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted

Bracket[]

Quarterfinals Semifinals Final
               
1 Netherlands Diede de Groot 77 3 5
China Zhu Zhenzhen 63 6 7
China Zhu Zhenzhen 6 0 4
Netherlands Aniek van Koot 1 6 6
Netherlands Marjolein Buis 67 4
Netherlands Aniek van Koot 79 6
Netherlands Aniek van Koot 2 2
2 Japan Yui Kamiji 6 6
South Africa Kgothatso Montjane 6 6
Germany Sabine Ellerbrock 0 1
South Africa Kgothatso Montjane 3 5
2 Japan Yui Kamiji 6 7
United Kingdom Jordanne Whiley 2 65
2 Japan Yui Kamiji 6 77

References[]

External links[]

Retrieved from ""