2022 Australian Open – Wheelchair women's singles

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Wheelchair women's singles
2022 Australian Open
ChampionNetherlands Diede de Groot
Runner-upNetherlands Aniek van Koot
Final score6–1, 6–1
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends
← 2021 · Australian Open ·  →

Defending champion Diede de Groot[1] successfully defended her title, defeating Aniek van Koot in the final, 6–1, 6–1 to win the wheelchair women's singles title at the 2022 Australian Open.

Seeds[]

  1. Netherlands Diede de Groot (champion)
  2. Japan Yui Kamiji (quarterfinals)

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted
  • SR = Special ranking

Bracket[]

Quarterfinals Semifinals Final
               
1 Netherlands Diede de Groot 6 6
United States Dana Mathewson 2 1
1 Netherlands Diede de Groot 6 7
WC United Kingdom Lucy Shuker 0 5
China Zhu Zhenzhen 2 2
WC United Kingdom Lucy Shuker 6 6
1 Netherlands Diede de Groot 6 6
Netherlands Aniek van Koot 1 1
South Africa Kgothatso Montjane 6 64 7
Netherlands Jiske Griffioen 1 77 5
South Africa Kgothatso Montjane 3 4
Netherlands Aniek van Koot 6 6
Netherlands Aniek van Koot 7 7
2 Japan Yui Kamiji 5 5

References[]

  1. ^ "2021 Australian Open: de Groot, Davidson are 2021 Champions". Yonex. 11 January 2022. Retrieved 11 January 2022.

External links[]

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