Barkley Township, Jasper County, Indiana

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Barkley Township
Location in Jasper County
Location in Jasper County
Coordinates: 41°01′33″N 87°04′20″W / 41.02583°N 87.07222°W / 41.02583; -87.07222Coordinates: 41°01′33″N 87°04′20″W / 41.02583°N 87.07222°W / 41.02583; -87.07222
CountryUnited States
StateIndiana
CountyJasper
Government
 • TypeIndiana township
Area
 • Total59.92 sq mi (155.2 km2)
 • Land59.9 sq mi (155 km2)
 • Water0.01 sq mi (0.03 km2)  0.02%
Elevation
689 ft (210 m)
Population
 (2010)
 • Total900
 • Density15/sq mi (6/km2)
GNIS feature ID0453095

Barkley Township is one of thirteen townships in Jasper County, Indiana, United States. As of the 2010 census, its population was 900 and it contained 362 housing units.[1]

History[]

Barkley Township was established in 1838. It was named for Henry Barkley, Sr.[2]

Geography[]

According to the 2010 census, the township has a total area of 59.92 square miles (155.2 km2), of which 59.9 square miles (155 km2) (or 99.97%) is land and 0.01 square miles (0.026 km2) (or 0.02%) is water.[1]

Unincorporated towns[]

Extinct towns[]

  • Lewiston
  • Moody

Adjacent townships[]

Cemeteries[]

The township contains nine cemeteries: Brown, Dunkard, Hankle, Parkison, Prater, Price, Rees, Sandridge and Smith.

Major highways[]

Education[]

Barkley Township residents may request a free library card from the Jasper County Public Library.[3]

References[]

  • "Barkley Township, Jasper County, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2009-09-24.
  • United States Census Bureau cartographic boundary files
  1. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
  2. ^ A standard history of Jasper and Newton counties, Indiana. Lewis Publishing Company. 1916. p. 49.
  3. ^ "How do I get a library card?". Jasper County Public Library. Retrieved 8 March 2018.

External links[]

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