De Soto, Nebraska

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De Soto, Nebraska
Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W / 41.5011528; -96.0567083Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W / 41.5011528; -96.0567083
CountryUnited States
StateNebraska
CountyWashington
Elevation
1,007 ft (307 m)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code(s)402

De Soto is an unincorporated community in Washington County, Nebraska, United States.[1] It was named in honor of the sixteenth-century Spanish explorer, Hernando De Soto.[2] De Soto was founded in 1855 and served as the county seat from 1858-1866. During its heyday, the town hosted many flourishing new businesses: hotels, saloons, stores, newspapers and banks.[3]

De Soto contains farmland with about three families residing there.[4]

References[]

  1. ^ U.S. Geological Survey Geographic Names Information System: De Soto, Nebraska
  2. ^ http://www.nebraskahistory.org/lib-arch/research/public/municipal_finding_aids/de_soto_ne.pdf
  3. ^ "Archived copy". Archived from the original on 2008-10-11. Retrieved 2008-06-24.CS1 maint: archived copy as title (link)
  4. ^ kancoll.com

External links[]



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