Oak Hill (Herkimer County, New York)
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Oak Hill | |
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Oak Hill Location of Oak Hill within New York Oak Hill Oak Hill (the United States) | |
Highest point | |
Elevation | 984 feet (300 m) |
Coordinates | 43°03′03″N 75°02′15″W / 43.05083°N 75.03750°W / 43.05083; -75.03750Coordinates: 43°03′03″N 75°02′15″W / 43.05083°N 75.03750°W / 43.05083; -75.03750[1] |
Geography | |
Location | NW of Herkimer, New York, U.S. |
Topo map | USGS Ilion |
Oak Hill is a summit located in Central New York Region of New York located in the Town of Herkimer in Herkimer County, northwest of Herkimer.
References[]
- ^ "Oak Hill". Geographic Names Information System. United States Geological Survey. Retrieved 2017-12-08.
Retrieved from ""
Categories:
- Mountains of Herkimer County, New York
- Mountains of New York (state)
Hidden categories:
- Coordinates on Wikidata