Osborne Hill
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Summit in Central New York, US
Osborne Hill | |
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Osborne Hill Location of Osborne Hill within New York Osborne Hill Osborne Hill (the United States) | |
Highest point | |
Elevation | 1,299 feet (396 m) |
Coordinates | 43°05′12″N 75°01′52″W / 43.08667°N 75.03111°W / 43.08667; -75.03111Coordinates: 43°05′12″N 75°01′52″W / 43.08667°N 75.03111°W / 43.08667; -75.03111[1] |
Geography | |
Location | NW of Herkimer, New York, U.S. |
Topo map | USGS Ilion |
Osborne Hill is a summit in Central New York Region of New York in the town of Herkimer in Herkimer County, northwest of the village of Herkimer.
References[]
- ^ "Osborne Hill". Geographic Names Information System. United States Geological Survey. Retrieved 2017-12-08.
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