Sandusky, Iowa

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Sandusky, Iowa
Census-designated place
Sandusky is located in Iowa
Sandusky
Sandusky
Coordinates: 40°27′52″N 91°23′13″W / 40.46444°N 91.38694°W / 40.46444; -91.38694Coordinates: 40°27′52″N 91°23′13″W / 40.46444°N 91.38694°W / 40.46444; -91.38694
Country United States
StateIowa
CountyLee
TownshipsJackson
Montrose
Area
[1]
 • Total6.91 km2 (2.67 sq mi)
 • Land3.69 km2 (1.42 sq mi)
 • Water3.22 km2 (1.24 sq mi)
Elevation
[2]
166 m (543 ft)
Population
 (2020)
297
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP Code
52632 (Keokuk)
Area code(s)319
FIPS code19-70545
GNIS feature ID2804144[2]

Sandusky is an unincorporated community and census-designated place (CDP) in Lee County, Iowa, United States. It is in the southeast part of the county, on the west bank of the Mississippi River 4 miles (6 km) north of Keokuk, the county seat, and 6 miles (10 km) south of Montrose.

Sandusky was first listed as a CDP prior to the 2020 census. As of the 2020 census, its population was 297. [3]

History[]

Founded in the 1800s, Sandusky's population was 85 in 1902,[4] and 60 in 1925.[5]

References[]

  1. ^ "2020 U.S. Gazetteer Files – Iowa". United States Census Bureau. Retrieved May 11, 2021.
  2. ^ a b "Sandusky Census Designated Place". Geographic Names Information System. United States Geological Survey.
  3. ^ "2020: DEC Redistricting Data (PL 94-171)". United States Census Bureau. Retrieved November 18, 2021.
  4. ^ Cram's Modern Atlas: The New Unrivaled New Census Edition. J. R. Gray & Company. 1902. pp. 203–207.
  5. ^ Company, Rand McNally and (1925). Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States,territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. p. 190.


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