Steuben Hill
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Steuben Hill | |
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Steuben Hill Location of Steuben Hill within New York Steuben Hill Steuben Hill (the United States) | |
Highest point | |
Elevation | 1,138 feet (347 m) |
Coordinates | 43°03′28″N 75°01′27″W / 43.05778°N 75.02417°W / 43.05778; -75.02417Coordinates: 43°03′28″N 75°01′27″W / 43.05778°N 75.02417°W / 43.05778; -75.02417[1] |
Geography | |
Location | NW of Herkimer, New York, U.S. |
Topo map | USGS Ilion |
Steuben Hill is a summit located in Central New York Region of New York located in the Town of Herkimer in Herkimer County, northwest of Herkimer.
References[]
- ^ "Steuben Hill". Geographic Names Information System. United States Geological Survey. Retrieved 2017-12-08.
Retrieved from ""
Categories:
- Mountains of Herkimer County, New York
- Mountains of New York (state)
Hidden categories:
- Coordinates on Wikidata