The 1828 United States presidential election in New York took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President. For this election, New York used the Congressional District Method of choosing electors, with 34 of its electors being chosen by the winner in each of the state's congressional districts, and the remaining two being chosen by the first 34 electors. Jackson won 18 congressional districts while Adams won 16. This election marks the first time New York did not chose its electoral votes through its State Legislature.[2]
New York voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won New York by a margin of 2.9%.
Results[]
1828 United States presidential election in New York[3]
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
Andrew Jackson
139,412
51.45%
20
National Republican
John Quincy Adams
131,563
48.55%
16
Totals
270,975
100.0%
36
See also[]
United States presidential elections in New York
References[]
^Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
^Moore, John L., ed. (1985). Congressional Quarterly's Guide to U.S. Elections (2nd ed.). Washington, D.C.: Congressional Quarterly, Inc. p. 254-56.