The 1840 United States presidential election in New York took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.
New York voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New York by a narrow margin of 3.00%.
Results[]
1840 United States presidential election in New York[2]
Party
Candidate
Running mate
Popular vote
Electoral vote
Count
%
Count
%
Whig
William Henry Harrison of Ohio
John Tyler of Virginia
226,001
51.18%
42
100.00%
Democratic
Martin Van Buren of New York
Richard M. Johnson of Kentucky
212,733
48.18%
0
0.00%
Liberty
James G. Birney of New York
Thomas Earle of Pennsylvania
2,809
0.64%
0
0.00%
Total
441,543
100.00%
42
100.00%
See also[]
United States presidential elections in New York
References[]
^Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.