1864 United States presidential election in New York

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1864 United States presidential election in New York

← 1860 November 8, 1864 1868 →
Turnout89.3%[1] Decrease 6.2 pp
  Abraham Lincoln November 1863.jpg GeorgeMcClellan2 (cropped).jpg
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 33 0
Popular vote 368,735 361,986
Percentage 50.46% 49.54%

New York Presidential Election Results 1864.svg
County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

The 1864 United States presidential election in New York took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

New York voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won the state by a bare margin of 0.92%.

Results[]

1864 United States presidential election in New York[2]
Party Candidate Votes Percentage Electoral votes
National Union Abraham Lincoln 368,735 50.46% 33
Democratic George B. McClellan 361,986 49.54% 0
Totals 730,721 100.0% 33

See also[]

  • United States presidential elections in New York

References[]

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1864 Presidential General Election Results - New York".


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