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Election for the governorship of the U.S. state of Iowa
1869 Iowa gubernatorial election
Nominee
Samuel Merrill
George Gillespie
Party
Republican
Democratic
Popular vote
97,243
57,287
Percentage
62.93%
37.07%
Governor before election
Samuel Merrill
Republican
Elected Governor
Samuel Merrill
Republican
The 1869 Iowa gubernatorial election was held on October 12, 1869. Incumbent Republican Samuel Merrill defeated Democratic nominee George Gillespie with 62.93% of the vote.
General election [ ]
Candidates [ ]
Samuel Merrill, Republican
George Gillespie, Democratic
Results [ ]
References [ ]
Categories :
Iowa gubernatorial elections 1869 United States gubernatorial elections Hidden categories:
Articles with short description Short description matches Wikidata