1948 Iowa gubernatorial election

1948 Iowa gubernatorial election

← 1946 November 2, 1948 1950 →

Nominee William S. Beardsley Carroll O. Switzer Party Republican Democratic Popular vote 553,900 434,432 Percentage 55.68% 43.67%

County results Beardsley:      50–60%      60–70%      70–80% Switzer:      50–60%

Governor before election Robert D. Blue Republican Elected Governor William S. Beardsley Republican

Elections in Iowa
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The 1948 Iowa gubernatorial election was held on November 2, 1948. Republican nominee William S. Beardsley defeated Democratic nominee Carroll O. Switzer with 55.68% of the vote.

Primary elections[]

Primary elections were held on June 7, 1948.^[1]

Democratic primary[]

Candidates[]

• Carroll O. Switzer, Polk County Attorney

Results[]

Republican primary[]

Candidates[]

• William S. Beardsley, State Representative
• Robert D. Blue, incumbent Governor

Results[]

General election[]

Candidates[]

Major party candidates

• William S. Beardsley, Republican
• Carroll O. Switzer, Democratic

Other candidates

• C. E. Bierderman, Progressive
• Marvin Galbreath, Prohibition
• William F. Leonard, Socialist

Results[]

References[]