Election for the governorship of the U.S. state of Iowa
1944 Iowa gubernatorial election
Nominee
Robert D. Blue
Richard F. Mitchell
Party
Republican
Democratic
Popular vote
561,827
437,684
Percentage
56.01%
43.63%
County results
Blue: 50-60% 60-70% 70-80%
Mitchell: 50-60%
Governor before election
Bourke B. Hickenlooper
Republican
Elected Governor
Robert D. Blue
Republican
The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.
Primary elections [ ]
Primary elections were held on June 5, 1944.[1]
Democratic primary [ ]
Candidates [ ]
Richard F. Mitchell , former Associate Justice of the Iowa Supreme Court
Results [ ]
Republican primary [ ]
Candidates [ ]
Robert D. Blue , incumbent Lieutenant Governor
Henry W. Burma, Speaker of the Iowa House of Representatives
Milton W. Strickler, former State Representative
Results [ ]
General election [ ]
Candidates [ ]
Major party candidates
Robert D. Blue, Republican
Richard F. Mitchell, Democratic
Other candidates
Glen Williamson, Prohibition
Hugo Bockewitz, Socialist
Results [ ]
References [ ]
President U.S. Senate U.S. House
Alabama
Alaska Territory
Arizona
Arkansas
California
Colorado
Connecticut
Delaware
Florida
Georgia
Hawaii Territory
Idaho
Illinois
Indiana
Iowa
Kansas
Kentucky
Louisiana
Maine
Maryland
Massachusetts
Michigan
Minnesota
Mississippi
Missouri
Montana
Nebraska
Nevada
New Hampshire
New Jersey
New Mexico
New York
North Carolina
North Dakota
Ohio
Oklahoma
Oregon
Pennsylvania
Puerto Rico
Rhode Island
South Carolina
South Dakota
Tennessee
Texas
Utah
Vermont
Virginia
Washington
West Virginia
Wisconsin
Wyoming
State governors State legislatures