1945 U.S. National Championships – Women's singles

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Women's singles
1945 U.S. National Championships
ChampionUnited States Sarah Palfrey Cooke[1]
Runner-upUnited States Pauline Betz
Final score3–6, 8–6, 6–4
Details
Draw32
Seeds8
Events
Singles men women
Doubles
← 1944 · U.S. National Championships · 1946 →

Second-seeded Sarah Palfrey Cooke defeated first-seeded Pauline Betz 3–6, 8–6, 6–4 in the final to win the women's singles tennis title at the 1945 U.S. National Championships.[1]

Seeds[]

The eight seeded U.S. players are listed below. Sarah Palfrey Cooke is the champion; others show in brackets the round in which they were eliminated.[2][3]

  1. United States Pauline Betz (Finalist)
  2. United States Sarah Palfrey Cooke (Champion)
  3. United States Margaret Osborne (Quarterfinalist)
  4. United States Louise Brough (Semifinalist)
  5. United States Patricia Todd (Quarterfinalist)
  6. United States Mary Arnold (Quarterfinalist)
  7. United States Dorothy Bundy (Quarterfinalist)
  8. United States Doris Hart (Semifinalist)

One foreign player was seeded.

  1. Argentina Mary Terán de Weiss (Second round)

Draw[]

Final eight[]

Quarterfinals Semifinals Finals
               
2 United States Sarah Palfrey Cooke 6 6
7 United States Dorothy Bundy 3 4
2 United States Sarah Palfrey Cooke 6 6
4 United States Louise Brough 3 4
4 United States Louise Brough 6 6
5 United States Patricia Todd 2 4
2 United States Sarah Palfrey Cooke 3 8 6
1 United States Pauline Betz 6 6 4
1 United States Pauline Betz 0 6 6
6 United States Mary Arnold 6 4 4
1 United States Pauline Betz 6 6
8 United States Doris Hart 3 2
3 United States Margaret Osborne 2 3
8 United States Doris Hart 6 6

References[]

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 470. ISBN 978-0942257700.
  2. ^ Official Tennis Guide 1946. [New York City]: A.S. Barnes and Company. 1946. pp. 37–39, 41.
  3. ^ "Parker, Betz Top Seeded". The Milwaukee Sentinel. AP. August 24, 1945. p. 5 (part 2).
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