1929 U.S. National Championships – Women's singles

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Women's singles
1929 U.S. National Championships
ChampionUnited States Helen Wills
Runner-upUnited Kingdom Phoebe Holcroft Watson[1]
Final score6–4, 6–2
Events
Singles men women
Doubles
← 1928 · U.S. National Championships · 1930 →

First-seeded Helen Wills defeated Phoebe Holcroft Watson 6–4, 6–2 in the final to win the women's singles tennis title at the 1929 U.S. National Championships. It was her sixth U.S. National singles title and her third in a row.[1][2][3]

Seeds[]

The tournament used a list of eight U.S. players and six foreign players for seeding the women's singles event. Helen Wills is the champion; others show in brackets the round in which they were eliminated.[4]

Draw[]

Final eight[]

Quarterfinals Semifinals Finals
               
1 United States Helen Wills 6 6
(3) United Kingdom Peggy Saunders Michell 0 1
1 United States Helen Wills 6 6
4 United States Molla Bjurstedt Mallory 0 0
4 United States Molla Bjurstedt Mallory 6 6
(1) United Kingdom Betty Nuthall 3 3
1 United States Helen Wills 6 6
(2) United Kingdom Phoebe Holcroft Watson 4 2
3 United States Edith Cross 6 1 3
(2) United Kingdom Phoebe Holcroft Watson 2 6 6
(2) United Kingdom Phoebe Holcroft Watson 6 3 6
2 United States Helen Jacobs 1 6 1
6 United States 2 2
2 United States Helen Jacobs 6 6

References[]

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 469. ISBN 978-0942257700.
  2. ^ "Helen Wills Wins National Tilt in Eighteen Minutes". The Lewiston Daily Sun. AP. August 20, 1929. p. Eleven – via Google News Archive.
  3. ^ "Helen Wills Takes Sixth National Title". Chicago Tribune. AP. August 25, 1929. p. 1, Part 2.
  4. ^ "Helen Wills Likely to Play her Rival". Sarasota Herald-Tribune. AP. August 14, 1929. p. Six – via Google News Archive.
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