1996 Fed Cup Americas Zone Group I – Knockout Stage
The Knockout Stage of the 1996 Fed Cup Americas Zone Group I was the final stage of the Zonal Competition involving teams from the Americas. Those that qualified for this stage placed first and second in their respective pools.
Placing | Pool A | Pool B |
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3 | ![]() |
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4 | ![]() |
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The four teams were then randomly drawn into a two-stage knockout tournament, with the winner advancing to the World Group II Play-offs.
Draw[]
Semifinals 27 April |
Final 28 April | ||||||||||||
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Semifinals[]
Chile vs. Brazil[]
![]() Chile 2 |
, Santiago, Chile 27 April 1996 Red clay (outdoors) |
![]() Brazil 1 | |||||||||||||||||||||||||||||
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Colombia vs. Venezuela[]
![]() Colombia 2 |
, Santiago, Chile 27 April 1996 Red clay (outdoors) |
![]() Venezuela 1 | |||||||||||||||||||||||||||||
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Final[]
Chile vs. Colombia[]
![]() Chile 2 |
, Santiago, Chile 28 April 1996 Red clay (outdoors) |
![]() Colombia 1 | |||||||||||||||||||||||||||||
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Chile advanced to the World Group II Play-offs, where they were drawn against
Croatia. However, they lost 0–5, and thus returned to the Americas Zone Group I in 1997.[4]
See also[]
- Fed Cup structure
References[]
- ^ "Chile v Brazil". fedcup.com.
- ^ "Colombia v Venezuela". fedcup.com.
- ^ "Chile v Colombia". fedcup.com.
- ^ "Chile v Croatia". fedcup.com.
External links[]
Categories:
- 1996 Fed Cup Americas Zone