2018 St. Petersburg Ladies' Trophy – Doubles

Doubles
2018 St. Petersburg Ladies' Trophy
Champions	Timea Bacsinszky Vera Zvonareva
Runners-up	Alla Kudryavtseva Katarina Srebotnik
Final score	2–6, 6–1, [10–3]
Events
Singles Doubles
← 2017 · St. Petersburg Ladies' Trophy · 2019 →

Jeļena Ostapenko and Alicja Rosolska were the defending champions, but Ostapenko chose not to participate this year. Rosolska played alongside Lara Arruabarrena, but lost in the first round to Alla Kudryavtseva and Katarina Srebotnik.

First-time pairings Timea Bacsinszky and Vera Zvonareva won the title, defeating Kudryavtseva and Srebotnik in the final, 2–6, 6–1, [10–3].

Seeds[]

Draw[]

Key[]

Draw[]

	First Round							Quarterfinals							Semifinals							Final
	1	G Dabrowski Y Xu	6	6
		V Kudermetova L Marozava	2	4				1	G Dabrowski Y Xu	1	77	[10]
		R Olaru O Savchuk	3	2					S Errani K Flipkens	6	65	[6]
		S Errani K Flipkens	6	6											1	G Dabrowski Y Xu	4	2
	4	D Jurak R Voráčová	3	3												T Bacsinszky V Zvonareva	6	6
		A Kalinskaya V Lapko	6	6					A Kalinskaya V Lapko	6	3	[8]
	WC	V Pogrebnyak E Rybakina	0	0					T Bacsinszky V Zvonareva	3	6	[10]
		T Bacsinszky V Zvonareva	6	6																			T Bacsinszky V Zvonareva	2	6	[10]
		L Arruabarrena A Rosolska	3	0																			A Kudryavtseva K Srebotnik	6	1	[3]
		A Kudryavtseva K Srebotnik	6	6					A Kudryavtseva K Srebotnik	7	4	[10]
		M Barthel N Geuer	6	6					M Barthel N Geuer	5	6	[8]
	3	N Melichar K Peschke	1	2												A Kudryavtseva K Srebotnik	6	3	[11]
		Y Sizikova D Yastremska	6	6											2	R Atawo A-L Grönefeld	4	6	[9]
		P Monova A Potapova	1	3					Y Sizikova D Yastremska	3	1
		N Dzalamidze X Knoll	2	2				2	R Atawo A-L Grönefeld	6	6
	2	R Atawo A-L Grönefeld	6	6

References[]

• Main Draw