Benton Township, Elkhart County, Indiana

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Benton Township
Location of Benton Township in Elkhart County
Location of Benton Township in Elkhart County
Coordinates: 41°28′55″N 85°42′27″W / 41.48194°N 85.70750°W / 41.48194; -85.70750Coordinates: 41°28′55″N 85°42′27″W / 41.48194°N 85.70750°W / 41.48194; -85.70750
CountryUnited States
StateIndiana
CountyElkhart
Government
 • TypeIndiana township
Area
 • Total35.9 sq mi (93 km2)
 • Land35.84 sq mi (92.8 km2)
 • Water0.06 sq mi (0.2 km2)
Elevation853 ft (260 m)
Population
 (2010)
 • Total2,963
 • Density82.7/sq mi (31.9/km2)
FIPS code18-04798[2]
GNIS feature ID453105

Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2010 census, its population was 2,963.[3]

Geography[]

According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.84 square miles (92.8 km2) (or 99.83%) is land and 0.06 square miles (0.16 km2) (or 0.17%) is water.[3]

Cities and towns[]

Unincorporated towns[]

Adjacent townships[]

Major highways[]

Cemeteries[]

The township contains two cemeteries: Brown and Hire.

References[]

  • "Benton Township, Elkhart County, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2009-09-24.
  • United States Census Bureau cartographic boundary files

External links[]


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