Sevastopol, Indiana

From Wikipedia, the free encyclopedia
Sevastopol, Indiana
Sevastopol is located in Indiana
Sevastopol
Sevastopol
Sevastopol is located in the United States
Sevastopol
Sevastopol
Coordinates: 41°07′45″N 86°01′08″W / 41.12917°N 86.01889°W / 41.12917; -86.01889Coordinates: 41°07′45″N 86°01′08″W / 41.12917°N 86.01889°W / 41.12917; -86.01889
CountryUnited States
StateIndiana
CountyKosciusko
TownshipFranklin
Elevation879 ft (268 m)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
46510
FIPS code18-68760[2]
GNIS feature ID443221

Sevastopol is an unincorporated community in Franklin Township, Kosciusko County, in the U.S. state of Indiana.[3]

History[]

Sevastopol was platted in 1855.[4] Its name commemorates the Siege of Sevastopol (1854–55).[5] A post office was established at Sevastopol in 1858, and remained in operation until it was discontinued in 1902.[6]

Geography[]

Sevastopol is located in the far southwest corner of the county, five miles from Mentone, seven from Burket, and 15 from Warsaw, the county seat.

References[]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ^ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. ^ "Sevastopol, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2017-06-07.
  4. ^ Biographical and Historical Record of Kosciusko County, Indiana. Lewis Publishing Company. 1887. p. 731.
  5. ^ Royse, L. W. (1919). A Standard History of Kosciusko County, Indiana. Lewis Publishing Company. p. 379.
  6. ^ "Kosciusko County". Jim Forte Postal History. Retrieved 25 November 2014.


Retrieved from ""