Seward Township, Kosciusko County, Indiana

From Wikipedia, the free encyclopedia
Seward Township
Township
Map highlighting Seward Township, Kosciusko County, Indiana.svg
Coordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°W / 41.10806; -85.94611Coordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°W / 41.10806; -85.94611
CountryUnited States
StateIndiana
CountyKosciusko
Government
 • TypeIndiana township
Area
 • Total36.27 sq mi (93.9 km2)
 • Land34.98 sq mi (90.6 km2)
 • Water1.3 sq mi (3 km2)
Elevation
[1]
876 ft (267 m)
Population
 (2010)
 • Total2,567
 • Density73.4/sq mi (28.3/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code18-68796[2]
GNIS feature ID453840

Seward Township is one of seventeen townships in Kosciusko County, Indiana. As of the 2010 census, its population was 2,567 and it contained 1,385 housing units.[3]

Seward Township was organized in 1859.[4]

Geography[]

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km2), of which 34.98 square miles (90.6 km2) (or 96.44%) is land and 1.3 square miles (3.4 km2) (or 3.58%) is water.[3]

Cities and towns[]

References[]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ^ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
  4. ^ Biographical and Historical Record of Kosciusko County, Indiana. Lewis Publishing Company. 1887. p. 728.

External links[]


Stub icon

This Kosciusko County, Indiana location article is a stub. You can help Wikipedia by .

  • v
  • t
Retrieved from ""