The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.
New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%.
Results[]
1836 United States presidential election in New York[2]
Party
Candidate
Running mate
Popular vote
Electoral vote
Count
%
Count
%
Democratic
Martin Van Buren of New York
Richard M. Johnson of Kentucky
166,795
54.63%
42
100.00%
Whig
William Henry Harrison of Ohio
Francis Granger of New York
138,548
45.37%
0
0.00%
Total
305,343
100.00%
42
100.00%
See also[]
United States presidential elections in New York
References[]
^Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.