1956 U.S. National Championships – Women's singles
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Women's singles | |
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1956 U.S. National Championships | |
Champion | ![]() |
Runner-up | ![]() |
Final score | 6–3, 6–4 |
Seeds | 8 |
First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]
Seeds[]
The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.
Shirley Fry (Champion)
Althea Gibson (Finalist)
Louise Brough (Quarterfinalist)
Dorothy Knode (Quarterfinalist)
Margaret duPont (Quarterfinalist)
Shirley Bloomer (Semifinalist)
Betty Pratt (Semifinalist)
Darlene Hard (Quarterfinalist)
Draw[]
Key[]
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- r = Retired
Final eight[]
Quarterfinals | Semifinals | Finals | ||||||||||||||||||
1 | ![]() | 6 | 4 | 6 | ||||||||||||||||
5 | ![]() | 2 | 6 | 3 | ||||||||||||||||
1 | ![]() | 6 | 6 | |||||||||||||||||
6 | ![]() | 4 | 4 | |||||||||||||||||
6 | ![]() | 6 | 6 | |||||||||||||||||
3 | ![]() | 3 | 3 | |||||||||||||||||
1 | ![]() | 6 | 6 | |||||||||||||||||
2 | ![]() | 3 | 4 | |||||||||||||||||
4 | ![]() | 6 | 0 | 2 | ||||||||||||||||
7 | ![]() | 4 | 6 | 6 | ||||||||||||||||
8 | ![]() | 1 | 8 | |||||||||||||||||
2 | ![]() | 6 | 10 | |||||||||||||||||
8 | ![]() | 7 | 1 | |||||||||||||||||
2 | ![]() | 9 | 6 |
References[]
- ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
- ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
- ^ "National Tennis Championships Opens Today". The Free Lance-Star. AP. August 31, 1956. p. 12.
Categories:
- U.S. National Championships (tennis) by year – Women's singles
- 1956 in women's tennis
- 1956 in American women's sports
- 1956 U.S. National Championships (tennis)