1988 United States Senate election in Ohio

1988 United States Senate election in Ohio

← 1982 November 8, 1988 1994 →

Nominee Howard Metzenbaum George Voinovich Party Democratic Republican Popular vote 2,480,038 1,872,716 Percentage 57.0% 42.3%

County results Metzenbaum:      50–60%      60–70%      70–80% Voinovich:      50-60%      60-70%

U.S. senator before election Howard Metzenbaum Democratic Elected U.S. Senator Howard Metzenbaum Democratic

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The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.^[1] As of 2022, this is the last time in a presidential election year Ohio voted differently for president and for senate.

Major candidates[]

Democratic[]

• Howard Metzenbaum, incumbent U.S. Senator

Republican[]

• George Voinovich, Mayor of Cleveland and former Lieutenant Governor of Ohio.

Results[]

See also[]

• 1988 United States Senate elections

References[]