1998 Boston Cup – Doubles

Doubles
1998 Boston Cup
Champions	Lisa Raymond Rennae Stubbs
Runners-up	Mariaan de Swardt Mary Joe Fernández
Final score	6–4, 6–4
Events
Singles Doubles
←  · Boston Cup ·  →

Lisa Raymond and Rennae Stubbs won in the final 6–4, 6–4 against Mariaan de Swardt and Mary Joe Fernández.

Seeds[]

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

1. Lisa Raymond / Rennae Stubbs (Champions)
2. Naoko Kijimuta / Nana Miyagi (First Round)
3. Kristine Kunce / Corina Morariu (First Round)
4. Amanda Coetzer / Barbara Schett (First Round)

Draw[]

Key[]

	First Round							Quarterfinals							Semifinals							Final
	1	L Raymond R Stubbs	6	6
		E deLone S-T Wang	3	1				1	L Raymond R Stubbs	6	6
		N de Villiers L McShea	6	1	4				S Farina A Huber	4	3
		S Farina A Huber	1	6	6										1	L Raymond R Stubbs	7	6
	3	K Kunce C Morariu	2	2											Q	C Black I Selyutina	6	1
	Q	C Black I Selyutina	6	6				Q	C Black I Selyutina	6	4	6
		A Ellwood T Musgrave	w/o						A Ellwood T Musgrave	2	6	2
		O Barabanschikova E Likhovtseva																				1	Lisa Raymond Rennae Stubbs	6	6
		L Horn M Paz	4	3																			Mariaan de Swardt Mary Joe Fernández	4	4
		R McQuillan N Pratt	6	6					R McQuillan N Pratt	3	3
		C Cristea R Dragomir	1	7	6				C Cristea R Dragomir	6	6
	4	A Coetzer B Schett	6	6	2											C Cristea R Dragomir	3	7	4
		K Freye Y Yoshida	6	6												M de Swardt M J Fernández	6	5	6
	WC	S Kleinová B Rippner	2	1					K Freye Y Yoshida	3	3
		M de Swardt M J Fernández	6	7					M de Swardt M J Fernández	6	6
	2	N Kijimuta N Miyagi	1	6

External links[]

• 1998 Boston Cup Doubles Draw