1998 Paris Open

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1998 Paris Open
Date2–9 November
Edition26th
CategoryATP Masters Series
Draw48S / 24D
Prize money$2,300,000
SurfaceCarpet / indoor
LocationParis, France
VenuePalais omnisports de Paris-Bercy
Champions
Singles
United Kingdom Greg Rusedski[1]
Doubles
India Mahesh Bhupati / India Leander Paes[2]
← 1997 · Paris Masters · 1999 →

The 1998 Paris Open was a tennis tournament played on indoor carpet courts. It was the 26th edition of the Paris Masters, and is part of the ATP Masters Series of the 1998 ATP Tour. It took place at the Palais omnisports de Paris-Bercy in Paris, France, from 2 November through 9 November 1998. Greg Rusedski won the singles title.

Finals[]

Singles[]

United Kingdom Greg Rusedski defeated United States Pete Sampras 6–4, 7–6(7–4), 6–3

  • It was Greg Rusedski's 2nd title of the year and his 7th overall. It was his 1st Masters title of the year, and overall.

Doubles[]

India Mahesh Bhupati / India Leander Paes defeated Netherlands Jacco Eltingh / Netherlands Paul Haarhuis 6–4, 6–2

References[]

  1. ^ "1998 Paris – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1998 Paris – Doubles draw". Association of Tennis Professionals (ATP).

External links[]

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