2019 Hobart International – Doubles

Doubles
2019 Hobart International
Champions	Chan Hao-ching Latisha Chan
Runners-up	Kirsten Flipkens Johanna Larsson
Final score	6–3, 3–6, [10–6]
Events
Singles Doubles
← 2018 · Hobart International · 2020 →

Elise Mertens and Demi Schuurs were the defending champions, but Mertens chose not to participate and Schuurs chose to compete in Sydney instead.

Chan Hao-ching and Latisha Chan won the title, defeating Kirsten Flipkens and Johanna Larsson in the final, 6–3, 3–6, [10–6].

Seeds[]

Draw[]

Key[]

Draw[]

	First round							Quarterfinals							Semifinals							Final
	1	H-c Chan L Chan	6	7
		M Adamczak J Moore	4	5				1	H-c Chan L Chan	w/o
		V Lapko E Routliffe	7	0	[11]				D Jakupović S Santamaria
		D Jakupović S Santamaria	5	6	[13]										1	H-c Chan L Chan	6	6
	3	M Niculescu Z Yang	6	6											3	M Niculescu Z Yang	3	4
		X Jiang S Zhang	4	2				3	M Niculescu Z Yang	6	6
		R Olaru G Voskoboeva	6	6					R Olaru G Voskoboeva	1	4
		A Panova L Siegemund	4	3																		1	H-c Chan L Chan	6	3	[10]
	WC	Z Hives E Perez	3	7	[7]																	4	K Flipkens J Larsson	3	6	[6]
		D Jurak D Krawczyk	6	5	[10]				D Jurak D Krawczyk	1	4
		L Arruabarrena S Sorribes Tormo	4	5				4	K Flipkens J Larsson	6	6
	4	K Flipkens J Larsson	6	7											4	K Flipkens J Larsson	7	6
	WC	A Bai A Poulos	3	2												A Potapova D Yastremska	5	4
		A Potapova D Yastremska	6	6					A Potapova D Yastremska	6	77
		K Christian A Guarachi	6	3	[8]			2	I-C Begu M Buzărnescu	4	63
	2	I-C Begu M Buzărnescu	1	6	[10]

References[]

• Main Draw