Borough of Sebastopol

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Borough of Sebastopol
Victoria
Population7,800 (1992)[1]
 • Density1,025/km2 (2,655/sq mi)
Established1864
Area7.61 km2 (2.9 sq mi)
Council seatSebastopol
CountyGrenville
Sebastopol Council 1994.jpg

The Borough of Sebastopol was a local government area about 4 kilometres (2 mi) south of the regional city of Ballarat, Victoria, Australia. The borough covered an area of 7.61 square kilometres (2.9 sq mi), and existed from 1864 until 1994.

Sebastopol was incorporated as a borough on 1 October 1864.[2] On 6 May 1994, the Borough of Sebastopol was abolished, and, along with the City of Ballaarat, the Shire of Ballarat, and parts of the Shires of Bungaree, Buninyong, Grenville and Ripon, was merged into the newly created City of Ballarat.[3]

Population[]

Year Population
1954 3,265
1958 3,480*
1961 4,663
1966 4,966
1971 5,268
1976 5,941
1981 6,462
1986 7,011
1991 7,527

* Estimate in the 1958 Victorian Year Book.

References[]

  1. ^ Australian Bureau of Statistics, Victoria Office (1994). Victorian Year Book. pp. 49–52. ISSN 0067-1223.
  2. ^ Victorian Municipal Directory. Brunswick: Arnall & Jackson. 1992. Accessed at State Library of Victoria, La Trobe Reading Room.
  3. ^ Australian Bureau of Statistics (1 August 1995). Victorian local government amalgamations 1994-1995: Changes to the Australian Standard Geographical Classification (PDF). Commonwealth of Australia. ISBN 0-642-23117-6. Retrieved 5 January 2008.

Coordinates: 37°34′S 143°51′E / 37.567°S 143.850°E / -37.567; 143.850

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