Buchanan, Iowa

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Buchanan, Iowa
Buchanan, Iowa is located in Iowa
Buchanan, Iowa
Buchanan, Iowa
Coordinates: 41°45′54″N 91°14′49″W / 41.76500°N 91.24694°W / 41.76500; -91.24694Coordinates: 41°45′54″N 91°14′49″W / 41.76500°N 91.24694°W / 41.76500; -91.24694
CountryUnited States
StateIowa
CountyCedar
Elevation
761 ft (232 m)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code(s)563
GNIS feature ID454910[1]

Buchanan is an unincorporated community in Cedar County, Iowa, United States.[1]

History[]

It was named for Alexander Buchanan, a farmer who owned land near the original town site.[2] Alexander Buchanan was born in Cedar County in 1841.[3] Buchanan's population was 27 in 1902,[4] and 61 in 1925.[5]

References[]

  1. ^ a b "Buchanan". Geographic Names Information System. United States Geological Survey.
  2. ^ Aurner, Clarence Ray (1910). A Topical History of Cedar County, Iowa, Volume 1. S. J. Clarke. p. 150.
  3. ^ The History of Cedar County, Iowa: Containing a History of the County, Its Cities, Towns, etc. Western Historical Company. 1878. p. 715.
  4. ^ Cram's Modern Atlas: The New Unrivaled New Census Edition. J. R. Gray & Company. 1902. pp. 203–207.
  5. ^ Company, Rand McNally and (1925). Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States,territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. p. 190.


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