1840 United States presidential election in Ohio

1840 United States presidential election in Ohio

← 1836 October 30 - December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 21 0 Popular vote 148,157 124,782 Percentage 54.10% 45.57%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

Elections in Ohio
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The 1840 United States presidential election in Ohio took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 8.53%.

Results[]

See also[]

• United States presidential elections in Ohio

References[]

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