Douglas, Iowa

From Wikipedia, the free encyclopedia
Douglas, Iowa
Douglas is located in Iowa
Douglas
Douglas
Location of Douglas within the state of Iowa
Coordinates: 43°00′30″N 91°52′17″W / 43.00833°N 91.87139°W / 43.00833; -91.87139Coordinates: 43°00′30″N 91°52′17″W / 43.00833°N 91.87139°W / 43.00833; -91.87139[1]
Country United States
State Iowa
CountyFayette County
Elevation297 m (974 ft)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
GNIS feature ID463549[1]

Douglas is an unincorporated community in Fayette County, Iowa, United States. It is located near the junction of County Road B44 and Maple Road, three miles southwest of Eldorado.[1]

History[]

Douglas in Fayette County, Iowa, in 1903

Douglas was originally spelled Douglass. The population of the community was 216 in 1902,[2] and was 105 in 1925.[3]

References[]

  1. ^ a b c d U.S. Geological Survey Geographic Names Information System: Douglas, Iowa
  2. ^ Cram's Modern Atlas: The New Unrivaled New Census Edition. J. R. Gray & Company. 1902. pp. 203–207.
  3. ^ Company, Rand McNally and (1925). Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States,territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. p. 190.
Retrieved from ""