Harlan Township, Fayette County, Iowa

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Harlan Township
Township
Location in Fayette County
Location in Fayette County
Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250
Country United States
State Iowa
CountyFayette
Area
 • Total36.79 sq mi (95.28 km2)
 • Land36.76 sq mi (95.22 km2)
 • Water0.03 sq mi (0.07 km2)  0.07%
Elevation
1,145 ft (349 m)
Population
 (2010)
 • Total871
 • Density24/sq mi (9.1/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP codes
50655, 50662, 50681, 52142, 52164
GNIS feature ID0468005

Harlan Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 871.[1]

Geography[]

According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages[]

Adjacent townships[]

Cemeteries[]

The township contains these two cemeteries: Hope and Long Grove.

Major highways[]

Landmarks[]

  • City Park
  • Twin Bridges County Park (east quarter)

School districts[]

  • West Central Community School District

Political districts[]

References[]

  1. ^ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa". United States Census Bureau. Retrieved March 5, 2012.

External links[]

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