1988 Pan Pacific Open – Singles

Singles
1988 Pan Pacific Open
Champion	Pam Shriver
Runner-up	Helena Suková
Final score	7–5, 6–1
Details
Draw	28 (4 Q )
Seeds	8
Events
Singles Doubles
← 1987 · Pan Pacific Open · 1989 →

Gabriela Sabatini was the defending champion but did not compete that year.

Pam Shriver won in the final 7–5, 6–1 against Helena Suková.

Seeds[]

A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated. The top four seeds received a bye to the second round.

Draw[]

Key[]

Final[]

	Final
	1	Pam Shriver	7	6
	3	Helena Suková	5	1

Section 1[]

	First Round							Second Round							Quarterfinals							Semifinals
								1	P Shriver	6	6
		L Meskhi	6	6					L Meskhi	0	2
		B Schultz	3	1											1	P Shriver	6	7
		P Louie-Harper	7	6												P Louie-Harper	1	5
		E Smylie	6	2					P Louie-Harper	3	6	6
	Q	N Miyagi	2	3				8	P Fendick	6	2	3
	8	P Fendick	6	6																		1	P Shriver	6	6	6
																						5	L Savchenko	7	2	4
								4	N Zvereva	6	7
		K Okamoto	7	2	5				A Henricksson	3	5
		A Henricksson	5	6	7										4	N Zvereva	6	5
		L Bonder	6	7											5	L Savchenko	7	7
		H Witvoet	1	5					L Bonder	6	3	5
		R White	6	1	4			5	L Savchenko	2	6	7
	5	L Savchenko	1	6	6

Section 2[]

	First Round							Second Round							Quarterfinals							Semifinals
	6	C Lindqvist	3	6	0
		D Balestrat	6	1	6				D Balestrat	1	2
		E Inoue	6	7					E Inoue	6	6
	Q		2	5												E Inoue	4	5
	Q	T Mochizuki	4	3											3	H Suková	6	7
		B Gerken	6	6					B Gerken	6	6	2
								3	H Suková	3	7	6
																						3	H Suková	7	4	6
	7	A Minter	6	3	7																	2	M Maleeva	6	6	3
	LL	L Antonoplis	0	6	6			7	A Minter	1	6	6
		W Turnbull	2	0					G Fernández	6	4	2
		G Fernández	6	6											7	A Minter	4	2
	Q	R Hiraki	6	0											2	M Maleeva	6	6
		A Kijimuta	7	6					A Kijimuta	7	4	0
								2	M Maleeva	6	6	6

External links[]

• ITF tournament edition details