2018 ATP Finals – Doubles

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Doubles
2018 ATP Finals
ChampionsUnited States Mike Bryan
United States Jack Sock
Runners-upFrance Pierre-Hugues Herbert
France Nicolas Mahut
Final score5–7, 6–1, [13–11]
Events
Singles Doubles
← 2017 · ATP Finals · 2019 →

Henri Kontinen and John Peers were the two-time defending champions, but they only qualified for the first alternate spot.[1] Kontinen and Peers replaced Nikola Mektić and Alexander Peya for the last match in the round robin competition.

Mike Bryan and Jack Sock won the title, defeating Pierre-Hugues Herbert and Nicolas Mahut in the final, 5–7, 6–1, [13–11].

Seeds[]

  1. Austria Oliver Marach / Croatia Mate Pavić (round robin)
  2. Colombia Juan Sebastián Cabal / Colombia Robert Farah (semifinals)
  3. Poland Łukasz Kubot / Brazil Marcelo Melo (round robin)
  4. United Kingdom Jamie Murray / Brazil Bruno Soares (semifinals)
  5. United States Mike Bryan / United States Jack Sock (champions)
  6. South Africa Raven Klaasen / New Zealand Michael Venus (round robin)
  7. Croatia Nikola Mektić / Austria Alexander Peya (round robin, withdrew)
  8. France Pierre-Hugues Herbert / France Nicolas Mahut (final)

Alternates[]

  1. Finland Henri Kontinen / Australia John Peers (Replaced Mektić/Peya, Round robin)
  2. Netherlands Jean-Julien Rojer / Romania Horia Tecău (Did not play)

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted
  • SR = Special ranking

Finals[]

Semifinals Final
          
8 France Pierre-Hugues Herbert
France Nicolas Mahut
6 5 [10]
2 Colombia Juan Sebastián Cabal
Colombia Robert Farah
3 7 [5]
8 France Pierre-Hugues Herbert
France Nicolas Mahut
7 1 [11]
5 United States Mike Bryan
United States Jack Sock
5 6 [13]
4 United Kingdom Jamie Murray
Brazil Bruno Soares
3 6 [4]
5 United States Mike Bryan
United States Jack Sock
6 4 [10]

Group Knowles/Nestor[]

Austria Marach
Croatia Pavić
Poland Kubot
Brazil Melo
United States Bryan
United States Sock
France Herbert
France Mahut
RR W–L Set W–L Game W–L Standings
1 Austria Oliver Marach
Croatia Mate Pavić
6–7(4–7), 4–6 4–6, 6–7(4–7) 6–4, 7–6(7–3) 1–2 2–4 33–36 4
3 Poland Łukasz Kubot
Brazil Marcelo Melo
7–6(7–4), 6–4 3–6, 6–7(5–7) 2–6, 4–6 1–2 2–4 28–35 3
5 United States Mike Bryan
United States Jack Sock
6–4, 7–6(7–4) 6–3, 7–6(7–5) 2–6, 2–6 2–1 4–2 30–31 2
8 France Pierre-Hugues Herbert
France Nicolas Mahut
4–6, 6–7(3–7) 6–2, 6–4 6–2, 6–2 2–1 4–2 34–23 1

Group Llodra/Santoro[]

Colombia Cabal
Colombia Farah
United Kingdom Murray
Brazil Soares
South Africa Klaasen
New Zealand Venus
Croatia Mektić
Austria Peya
Finland Kontinen
Australia Peers
RR W–L Set W–L Game W–L Standings
2 Colombia Juan Sebastián Cabal
Colombia Robert Farah
4–6, 3–6 6–3, 7–6(7–5) 6–3, 6–4
(w/ Mektić/Peya)
2–1 4–2 32–28 2
4 United Kingdom Jamie Murray
Brazil Bruno Soares
6–4, 6–3 7–6(7–5), 4–6, [10–5] 3–6, 7–6(7–3), [10–3]
(w/ Kontinen/Peers)
3–0 6–2 35–31 1
6 South Africa Raven Klaasen
New Zealand Michael Venus
3–6, 6–7(5–7) 6–7(5–7), 6–4, [5–10] 7–6(7–5), 7–6(7–5)
(w/ Mektić/Peya)
1–2 3–4 35–37 3
7

9
Croatia Nikola Mektić
Austria Alexander Peya
Finland Henri Kontinen
Australia John Peers
3–6, 4–6
(w/ Mektić/Peya)
6–3, 6–7(3–7), [3–10]
(w/ Kontinen/Peers)
6–7(5–7), 6–7(5–7)
(w/ Mektić/Peya)
0–2

0–1
0–4

1–2
19–26

12–11
X

4

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-player ties, head-to-head records; 4. in three-player ties, percentage of sets won, then percentage of games won, then ATP rankings.[2]

References[]

  1. ^ "Draw Announced For 2018 Nitto ATP Finals". ATP. 5 November 2018.
  2. ^ "Semi-final Qualifying Procedure". Nitto ATP Finals. Retrieved 14 November 2018.

External links[]

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