Hardin Township, Pike County, Illinois

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Hardin Township
Township
Location in Pike County
Location in Pike County
Pike County's location in Illinois
Pike County's location in Illinois
CountryUnited States
StateIllinois
CountyPike
EstablishedNovember 8, 1853
Area
 • Total37.41 sq mi (96.9 km2)
 • Land37.39 sq mi (96.8 km2)
 • Water0.03 sq mi (0.08 km2)  0.08%
Population
 (2010)
 • Estimate 
(2016)[1]
206
 • Density5.7/sq mi (2.2/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
FIPS code17-149-32863

Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[2]

Geography[]

According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[2]

Demographics[]

Historical population
Census Pop. %±
2016 (est.)206[1]
U.S. Decennial Census[3]

References[]

  1. ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-28.
  3. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.

External links[]

Coordinates: 39°31′42″N 90°44′49″W / 39.52833°N 90.74694°W / 39.52833; -90.74694


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