1804 United States presidential election in Georgia

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1804 United States presidential election in Georgia
Flag of the State of Georgia (non-official).svg
← 1800 November 2 - December 15, 1804 1808 →
  Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee Thomas Jefferson
Party Democratic-Republican
Home state Virginia
Running mate George Clinton
Electoral vote 6
Percentage 100%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

Thomas Jefferson
Democratic-Republican

Electoral results in 1804. Georgia cast six electoral votes.

The 1804 presidential election in Georgia took place between November 2 to December 15, 1804, as part of the 1804 United States presidential election. As occurred at the time, the state legislatures chose six electors to represent the state in the election.

Results[]

Nationwide, Jefferson won in a landslide, winning all but two states[nb 1] and proving to be a very popular president in most areas. Georgia was no exception, with all six electors voting for Democratic-Republican candidate Thomas Jefferson and his running mate George Clinton, over the Federalist candidates Charles Pinckney and Rufus King.[1]

See also[]

Notes[]

  1. ^ In addition to these two states, Pinckney did win two electoral votes in Maryland.

References[]

  1. ^ "Presidential Election of 1804". 270toWin.com.
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